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C | 14 |
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Question The air in a tube open at both ends is sent into its fundamental resonance. One end of the tube is then closed and the air column is again set into its fundamental resonance. The resonant frequency ____ after the end is closed.
1) halves
2) stays the same
3) doubles
4) increases by a factor of 1.4
5) increases by a factor of 4.0 | |
Answer halves | |
| User | Added | Note | e | d |
|---|---|---|---|---|
| KillGorack | 2023-07-22 10:44:14 | The fundamental resonance (or the first harmonic) of a tube open at both ends is calculated as: f1 = v / (2 * L) where v is the speed of sound in air, and L is the length of the tube. When the tube is closed at one end, only odd harmonics are present, and the fundamental frequency (first harmonic) is given by: f1' = v / (4 * L) Comparing the two equations, we can see that when one end of the tube is closed, the fundamental frequency halves. Therefore, the correct answer is: halves |