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Question Consider two identical and symmetrical wave pulses on a string. Suppose the first pulse reaches the fixed end of the string and is reflected back and then meets the second pulse. When the two pulses overlap exactly, the superposition principle predicts that the amplitude of the resultant pulses, at that moment, will be what factor times the amplitude of one of the original pulses? | |
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| KillGorack | 2023-07-16 11:28:09 | When a wave pulse reaches the fixed end of a string, it is reflected and inverted, meaning that the direction of its amplitude changes (positive amplitudes become negative, and vice versa). If we have two identical and symmetrical wave pulses and one of them is reflected and inverted, when they meet and overlap exactly, the result according to the superposition principle will be that the amplitudes of the two pulses will add up algebraically. Since one pulse has been inverted, its amplitude will be the negative of the original amplitude. So when it meets with the second pulse (which has the same amplitude but opposite sign due to the reflection), the result will be an amplitude of 0. Therefore, the amplitude of the resultant pulse will be 0 times the amplitude of one of the original pulses. |