KillGorack / Physics 2010 / The tungsten filament of a light bulb has an operating temperature of about 2 100 K. If the emitting area of the filament is 1.0 cm2 , and its emissivity is 0.68, what is the power output of the light bulb? (s = 5.67*10^-8 W/m^2×K^4)

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Question The tungsten filament of a light bulb has an operating temperature of about 2 100 K. If the emitting area of the filament is 1.0 cm2 , and its emissivity is 0.68, what is the power output of the light bulb? (s = 5.67*10^-8 W/m^2×K^4)
Answer 75 W

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