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The following physics responses are provided by a student and, as such, should be considered in that context. While every effort is made for accuracy, absolute correctness cannot be fully guaranteed.
| Question | |
C | 11 |
I | |
Question Dmitri places one end of a copper rod in a heat reservoir and the other end in a heat sink. By what factor is the rate of heat flow changed when the temperature difference between the reservoir and sink is tripled? | |
Answer 3.0 | |
Notes
| User | Added | Note | e | d |
|---|---|---|---|---|
| KillGorack | 2023-07-08 18:01:44 | The rate of heat flow (Q/t) through a material is given by the equation: Q/t = kA(T1 - T2)/L where: Q/t is the heat flow per unit time, k is the thermal conductivity of the material, A is the cross-sectional area, (T1 - T2) is the temperature difference between the two ends, L is the length of the material. From this equation, we can see that the rate of heat flow is directly proportional to the temperature difference (T1 - T2) between the two ends of the rod. This means that if you triple the temperature difference, you would also triple the rate of heat flow. So, the rate of heat flow changes by a factor of 3 when the temperature difference between the reservoir and sink is tripled. |
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