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C | 11 |
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Question Carly places one end of a steel bar in a Bunsen flame and the other end in an ice cube. By what factor is the rate of heat flow changed when the bar's cross-sectional area is doubled? | |
Answer 2 | |
| User | Added | Note | e | d |
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| KillGorack | 2023-07-08 18:00:22 | The rate of heat flow (Q/t) through a material is given by the equation: Q/t = kA(T1 - T2)/L where: Q/t is the heat flow per unit time, k is the thermal conductivity of the material, A is the cross-sectional area, (T1 - T2) is the temperature difference between the two ends, L is the length of the material. From this equation, it's clear that the rate of heat flow is directly proportional to the cross-sectional area. This means if you double the cross-sectional area (A), you would also double the rate of heat flow. So, the rate of heat flow changes by a factor of 2 when the bar's cross-sectional area is doubled. |