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The following physics responses are provided by a student and, as such, should be considered in that context. While every effort is made for accuracy, absolute correctness cannot be fully guaranteed.
| Question | |
C | 8 |
I | |
Question An object of mass m and moment of inertia I has rotational kinetic energy KR. Its angular momentum is: | |
Answer (2 IKR)^1/2 | |
Notes
| User | Added | Note | e | d |
|---|---|---|---|---|
| KillGorack | 2023-06-28 20:47:20 | The angular momentum (L) of an object is given by the product of its moment of inertia (I) and its angular velocity (ω). Mathematically, it can be expressed as: L = I * ω However, in this case, you mentioned that the object has rotational kinetic energy (KR), not the angular velocity. To establish a relationship between the angular momentum and the rotational kinetic energy, we need additional information. If we assume that the object is rotating about a fixed axis, we can use the equation for rotational kinetic energy: KR = (1/2) * I * ω^2 Rearranging this equation, we can solve for ω: ω^2 = (2 * KR) / I Taking the square root of both sides, we obtain: ω = √((2 * KR) / I) Now, substituting this expression for ω back into the equation for angular momentum: L = I * ω = I * √((2 * KR) / I) Simplifying further, we get: L = √(2 * I * KR) Therefore, the angular momentum (L) of the object with mass m, moment of inertia I, and rotational kinetic energy KR is given by √(2 * I * KR). |
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