KillGorack / Physics 2010 / An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4 000 miles). At this location, the acceleration due to gravity is what factor times the value of g at the Earth's surface?

The following physics responses are provided by a student and, as such, should be considered in that context. While every effort is made for accuracy, absolute correctness cannot be fully guaranteed.

Content
- Home
- Discussion
- Index
- Calendar
Analysis
- Graphical analysis

Question

C	7
I

Question An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4 000 miles). At this location, the acceleration due to gravity is what factor times the value of g at the Earth's surface?
Answer 1/4

Notes

User	Added	Note	e	d
KillGorack	2023-06-16 13:39:52	we are two radii away from th4 earths surface. "According to the inverse square law, the acceleration due to gravity decreases with the square of the distance from the center of the Earth." so if we are 2 radii away we are g/2^2 away (1/4)